vexpm1f(_:)
For each vector element, calculates ExpM1(x) = Exp(x) - 1. But, for small enough arguments, ExpM1(x) is expected to be more accurate than Exp(x) - 1.
Declaration
func vexpm1f(_: vFloat) -> vFloatFor each vector element, calculates ExpM1(x) = Exp(x) - 1. But, for small enough arguments, ExpM1(x) is expected to be more accurate than Exp(x) - 1.
func vexpm1f(_: vFloat) -> vFloat