---
title: "remainder(dividingBy:)"
framework: swift
role: symbol
role_heading: Instance Method
path: "swift/double/remainder(dividingby:)"
---

# remainder(dividingBy:)

Returns the remainder of this value divided by the given value.

## Declaration

```swift
func remainder(dividingBy other: Self) -> Self
```

## Parameters

- `other`: The value to use when dividing this value.

## Return Value

Return Value The remainder of this value divided by other.

## Discussion

Discussion For two finite values x and y, the remainder r of dividing x by y satisfies x == y * q + r, where q is the integer nearest to x / y. If x / y is exactly halfway between two integers, q is chosen to be even. Note that q is not x / y computed in floating-point arithmetic, and that q may not be representable in any available integer type. The following example calculates the remainder of dividing 8.625 by 0.75: let x = 8.625 print(x / 0.75) // Prints "11.5"

let q = (x / 0.75).rounded(.toNearestOrEven) // q == 12.0 let r = x.remainder(dividingBy: 0.75) // r == -0.375

let x1 = 0.75 * q + r // x1 == 8.625 If this value and other are finite numbers, the remainder is in the closed range -abs(other / 2)...abs(other / 2). The remainder(dividingBy:) method is always exact. This method implements the remainder operation defined by the IEEE 754 specification.

## See Also

### Performing Calculations

- [Floating-Point Operators for Double](swift/floating-point-operators-for-double.md)
- [addingProduct(_:_:)](swift/double/addingproduct(_:_:).md)
- [addProduct(_:_:)](swift/double/addproduct(_:_:).md)
- [squareRoot()](swift/double/squareroot().md)
- [formSquareRoot()](swift/double/formsquareroot().md)
- [formRemainder(dividingBy:)](swift/double/formremainder(dividingby:).md)
- [truncatingRemainder(dividingBy:)](swift/double/truncatingremainder(dividingby:).md)
- [formTruncatingRemainder(dividingBy:)](swift/double/formtruncatingremainder(dividingby:).md)
- [negate()](swift/double/negate().md)