---
title: "isDisjoint(with:)"
framework: swift
role: symbol
role_heading: Instance Method
path: "swift/set/isdisjoint(with:)-2onid"
---

# isDisjoint(with:)

Returns a Boolean value that indicates whether the set has no members in common with the given sequence.

## Declaration

```swift
func isDisjoint<S>(with other: S) -> Bool where Element == S.Element, S : Sequence
```

## Parameters

- `other`: A sequence of elements. other must be finite.

## Return Value

Return Value true if the set has no elements in common with other; otherwise, false.

## Discussion

Discussion In the following example, the employees set is disjoint with the elements of the visitors array because no name appears in both. let employees: Set = ["Alicia", "Bethany", "Chris", "Diana", "Eric"] let visitors = ["Marcia", "Nathaniel", "Olivia"] print(employees.isDisjoint(with: visitors)) // Prints "true"

## See Also

### Comparing Sets

- [==(_:_:)](swift/set/==(_:_:).md)
- [!=(_:_:)](swift/set/!=(_:_:).md)
- [isSubset(of:)](swift/set/issubset(of:)-1d7pp.md)
- [isSubset(of:)](swift/set/issubset(of:)-6qyo5.md)
- [isStrictSubset(of:)](swift/set/isstrictsubset(of:)-96vc3.md)
- [isStrictSubset(of:)](swift/set/isstrictsubset(of:)-787sx.md)
- [isSuperset(of:)](swift/set/issuperset(of:)-9iz62.md)
- [isSuperset(of:)](swift/set/issuperset(of:)-90hri.md)
- [isStrictSuperset(of:)](swift/set/isstrictsuperset(of:)-4d27m.md)
- [isStrictSuperset(of:)](swift/set/isstrictsuperset(of:)-58ejg.md)
- [isDisjoint(with:)](swift/set/isdisjoint(with:)-8ngmk.md)