---
title: ">>=(_:_:)"
framework: swift
role: symbol
role_heading: Operator
path: "swift/uint8/__=(_:_:)-8pj4c"
---

# >>=(_:_:)

Stores the result of shifting a value’s binary representation the specified number of digits to the right in the left-hand-side variable.

## Declaration

```swift
static func >>= <Other>(lhs: inout Self, rhs: Other) where Other : BinaryInteger
```

## Parameters

- `lhs`: The value to shift.
- `rhs`: The number of bits to shift lhs to the right.

## Discussion

Discussion The >>= operator performs a smart shift, which defines a result for a shift of any value. Using a negative value for rhs performs a left shift using abs(rhs). Using a value for rhs that is greater than or equal to the bit width of lhs is an overshift. An overshift results in -1 for a negative value of lhs or 0 for a nonnegative value. Using any other value for rhs performs a right shift on lhs by that amount. The following example defines x as an instance of UInt8, an 8-bit, unsigned integer type. If you use 2 as the right-hand-side value in an operation on x, the value is shifted right by two bits. var x: UInt8 = 30                 // 0b00011110 x >>= 2 // x == 7                         // 0b00000111 If you use 11 as rhs, x is overshifted such that all of its bits are set to zero. var y: UInt8 = 30                 // 0b00011110 y >>= 11 // y == 0                         // 0b00000000 Using a negative value as rhs is the same as performing a left shift using abs(rhs). var a: UInt8 = 30                 // 0b00011110 a >>= -3 // a == 240                       // 0b11110000

var b: UInt8 = 30                 // 0b00011110 b <<= 3 // b == 240                       // 0b11110000 Right shift operations on negative values “fill in” the high bits with ones instead of zeros. var q: Int8 = -30                 // 0b11100010 q >>= 2 // q == -8                        // 0b11111000

var r: Int8 = -30                 // 0b11100010 r >>= 11 // r == -1                        // 0b11111111